modify select query result

**USER4FUN** · 03-05-2006 06:13 PM

i am not sure how to do this and i would appreaciate any ideas

example if i have this in my table (www.webdeveloper.com)

IT would be modified to
info@webdeveloper.com
sales@webdeveloper.com
techsupport@webdeveloper.com

then i input a subject and a mesage and click on send, the modified data would become the email address that it will email out to.

where am i starting?
find a way to change the first 4 characters in very result and change it to the new variables

i.e
www.webdeveloper
change first 4 (www.)
to

$first ( which is equal to info@)
then
$second (which is equal to sales@)

I would appreaciate any ideas.

Thank you all

**Markbad311** · 03-05-2006 06:33 PM

$preg_replace??? I am not following your question to well the Title of the Post has to do with a query but in your message you are asking how to replace www. with something else..

**bokeh** · 03-05-2006 07:25 PM

Originally Posted by USER4FUN

I would appreaciate any ideas.

On sending spam? Don't do it. It spoils the web for everyone.

**USER4FUN** · 03-05-2006 11:07 PM

by no means am i going to spam.

to make you feel better, i swear on everything that is good i an not spamming, i hate spam.
.

to the previosue post,
yes sir, i am trying to find a way to reaplace the
www.
into different variable that would be declared in a different file.

list.inc

$first = info@;
$second = sales@;

thatis is pretty much it, i go arround and find the email address of the 500 domains that i have and need to contact.

I need to shoot out these probable emails
like

info@domain.com
sales@domain.com
and hope for a response so i can store their contact information. either that or visit each site and try to find out their contact email, and then look like an idiotfor losing the contact list file.

**Sheldon** · 03-06-2006 12:42 AM

PHP Code:


$domain = "webdeveloper.com";



echo("info@". $domain);

echo("contact@". $domain);

echo("a href=\"mailto:sales@". $domain ."\">sales@". $domain ."</a>);

**bokeh** · 03-06-2006 03:25 AM

Originally Posted by USER4FUN

by no means am i going to spam.

Originally Posted by USER4FUN

i go arround and find the email address of the 500 domains

Originally Posted by USER4FUN

I need to shoot out these probable emails
like

info@domain.com
sales@domain.com
and hope for a response

If it looks like a duck, walks like a duck and quacks like a duck, normally it's a duck.

**USER4FUN** · 03-06-2006 04:01 PM

i should have proof read my post, when i said i go arround
i mean to say instead of going arround.

i HAD a list of 500 domains that i deal with. their contact email was stored in a file that i lost.

i still had a backup of the domain name and i did not want to have to visit each domain by itself and look up their contact information.

with that being said, i dont think its a duck, nor does it quack like a duck therefore IT IS NOT A DUCK ( NOT SPAM) LOL

thank you all for your help.

incase any other readers have any other ideas, i will be checking this post again.

**USER4FUN** · 03-06-2006 04:26 PM

sorry but this will not work
quote

$domain = "webdeveloper.com";

echo("info@". $domain);
echo("contact@". $domain);
echo("a href=\"mailto:sales@". $domain ."\">sales@". $domain ."</a>);

/quote

it will not work beacause the result will be
info@www.webdeveloper.com

i need to replace the www. instead of add something infront of it.

thankx

**Sheldon** · 03-06-2006 04:33 PM

bull****

PHP Code:


$domain = "webdeveloper.com";

where is the www. in there?

**USER4FUN** · 03-06-2006 05:13 PM

I GOT IT, THANK YOU ALL FOR THE HELP

<html>
<head>

<title>Untitled</title>

</head>
<body>

<?

$replacer = 'www.';
$first = 'info@';
$second = 'sales@';
$contact = str_replace("$replacer", "$first", "$Domain");
$secontact = str_replace("$replacer", "$second", "$Domain");

echo "$contact<br>";
echo $secontact;

?>

</body>
</html>

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