php json_decode . Help please

[fireblade]

I have a varibale created in javascript as follows

var jsonData = {"data1" : "dataContent"};

when i pass this to server through ajax.. I am decoding

PHP Code:

$vars = json_decode($jsonData);


But I am not getting the correct result when printing this

PHP Code:

print_r($vars);


I am getting empty result.

Is there any error in this?

[mitya]

Well where are you declaring $jsonData? I can't see that you are.

Also, note that you don't need quotations around object property names, so the following two syntaxes will work the same:

var jsonData = {"data1" : "dataContent"};
var jsonData = {data1 : "dataContent"};

[rnd me]

Originally Posted by mitya

01
Also, note that you don't need quotations around object property names, so the following two syntaxes will work the same:

var jsonData = {"data1" : "dataContent"};
var jsonData = {data1 : "dataContent"};

Yes, you do need to quote JSON key names...

PHP's json_decode would fail without them, and how else would you store reserved name properties?

[rnd me]

Originally Posted by mitya

Also, note that you don't need quotations around object property names, so the following two syntaxes will work the same:

var jsonData = {"data1" : "dataContent"};
var jsonData = {data1 : "dataContent"};

Yes, you do need to quote JSON key names...

How else would you store a property named constructor?

[fireblade]

Yes,

I have quoted as follows..

var jsonData = {"data1" : "dataContent"};

I pass this to PHP through ajax and i get the variable to a php function as a post variable. and I start processing it.

before submitting I can test this in javascript like

alert(jsonData.data1);

it works fine. and am getting result "dataContent"

in the server result like below

PHP Code:

    public function deleteUsers($jsonData)
    {
        echo $jsonData; // this will print "[object Object]"
        $vars = json_decode($jsonData);
        print_r($vars); // nothing will be printed
    }


this is ma problem

[rnd me]

you're not running JSON.stringify() before you upload the javascript are you?

[fireblade]

WWOW...

2 thumbs.. This is what i wanted. Thanks my friend. It worked for me.