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@NogDogApr 18.2019 — #In interactive mode, and assuming I'm correctly interpreting the expected content of
So, I'd start by dumping the contents of
multiple instances of value output from single instance of value in array
So this is array i’m working with
Array ( [0] => Traditional Favourites [1] => Starters [2] => Mains )
looping through this using the following:
[code]
$val = $resultsCatTitle[‘CategoryTitle’];
$resultArrMainCatgTitle[] = $val;
reset($resultArrMainCatgTitle);
while (list($key, $val) = each($resultArrMainCatgTitle)) {
if($val === “Traditional Favourites”) {
echo $val;
}
there is only one instance of the value “Traditional Favourites” in the array but using echo $val puts out the following:
Traditional FavouritesTraditional FavouritesTraditional Favourites
I’ve also tried a for loop that too provides the same result. Is there a reason behind is? and how would I go about correcting this? It should only come back with 1 instance shouldn’t it?
__(replaced single back-ticks with `[code]…[/code]
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@NogDogApr 18.2019 — #In interactive mode, and assuming I'm correctly interpreting the expected content of $resultArrMainCatgTitle<i>
</i>php > $resultArrMainCatgTitle = ['Traditional Favourites', 'Starters', 'Mains'];
php > while (list($key, $val) = each($resultArrMainCatgTitle)) {
php { if($val === "Traditional Favourites") {
php { echo "$valn";
php { }
php { }
Traditional Favourites
php >
So, I'd start by dumping the contents of
$resultArrMainCatgTitle<i>
</i>die("<pre>".var_export($resultArrMainCatgTitle, 1)."</pre>");