if control for array

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Adem

Hello,

array post
Sample:
form

  

  <select size="8" name="day_of_week[]" id="day_of_week" multiple>  

		<option value="-1" selected="selected">*</option>
		<option value="0">Sunday</option>
		<option value="1">Monday</option>
		<option value="2">Tuesday</option>
		<option value="3">Wednesday</option>
		<option value="4">Thursday</option>
		<option value="5">Friday</option>
		<option value="6">Saturday</option>		
  </select>

if(is_array($POST['day_of_week']) && in_array(GOING TO HAPPEN HERE?, $POST['day_of_week'])){
echo "Selected day(s) of week";
}

if(is_array($_POST['day_of_week']) && in_array(GOING TO HAPPEN HERE?, $_POST['day_of_week'])){
echo "Selected day(s) of week";
}


// this is okay
if(is_array($_POST['day_of_week']) && in_array('-1', $_POST['day_of_week'])){
echo "Disabled day(s) of week";
}

Thanks

ginerjm

What is your question???

Adem

ginerjm;1287047 wrote:
What is your question???

I'm sorry, I do not know english

This question, Selected day of the week
if(is_array($POST['day_of_week']) && in_array(GOING TO HAPPEN HERE?, $POST['day_of_week'])){
echo "Selected day(s) of week";
}

ginerjm

Sorry - don't know what you want to find here.

Good luck.

Adem

Is selected day(s) of the week
if(??????????){

}

ginerjm

Sorry...

Adem

ginerjm;1287087 wrote:
Sorry...

Do you have any idea on this subject?
http://www.webdeveloper.com/forum/showthread.php?283245-How-do-I-run-local-files-Can-you-help

jedaisoul

You need to use the date function. There are a few variations:
- date('D') returns "Mon" to "Sun".
- date('l') returns "Monday" to "Sunday".
- date('N') returns "1" (Monday) to "7" (Sunday).

So use syntax like:

if (date('N')=='1') { do this for Monday }
elseif (date('N')=='2' { etc... }

or to test multiple days in a single if statement use STRPOS. However, strpos has a weakness in that matching the first character returns 0, which can be interprted as false instead of true. So you need to either use '===' as in:

if !(strpos('1357',date('N')) === false) { do this if Mon, Wed, Fri or Sun }
else ( do this if Tue, Thu or Sat }

or use a dummy character as the first character in the test string that will never match. E.g. Using '_' (underscore) as the first character:

if (strpos('_1357',date('N')) == true) { do this if Mon, Wed, Fri or Sun }
else ( do this if Tue, Thu or Sat }

Note: I haven't tested the above code, so it may need tweaking, but this should give you an idea of how to do it.

Adem

jedaisoul, Thank you for reply.

Okay, not the problem
1....7
I need the code to control two
Only if() the code

array name="day_of_week[]"

Disable week days, selected() value(-1)

  <select size="8" name="day_of_week[]" id="day_of_week" multiple>  

        <option value="-1" selected="selected">*</option>
        <option value="1">Sunday</option>
        <option value="2">Monday</option>
        <option value="3">Tuesday</option>
        <option value="4">Wednesday</option>
        <option value="5">Thursday</option>
        <option value="6">Friday</option>
        <option value="7">Saturday</option>        

  </select>

First control: Disable week days, a selection, a value (-1)
if($_POST['day_of_week']=='-1'){
Codes for disable week days
I have this code available
}

Second control: Enable week days, selection a or multi day(s).
Note: Are excluded value (-1) "Not select " " and day(s) of week the same time!"
// days "1,2,3,4,5,6,7"
if($_POST['day_of_week']>-1){ // I need some help here
Codes for aktive week day(s)
I have this code available
}

I've been using it for the dates of the week
I change the, 1....7, no problem
and I use this date('N'), no problem

               if($sonraki_gun=='0'){
          $h_tarihi=date('d.m.Y', strtotime('noon sunday')); // Pazar
          }elseif($sonraki_gun=='1'){
          $h_tarihi=date('d.m.Y', strtotime('noon monday')); // Pazartesi
          }elseif($sonraki_gun=='2'){
          $h_tarihi=date('d.m.Y', strtotime('noon tuesday')); // Sal&#305;
          }elseif($sonraki_gun=='3'){
          $h_tarihi=date('d.m.Y', strtotime('noon wednesday')); // Çar&#351;amba
          }elseif($sonraki_gun=='4'){
          $h_tarihi=date('d.m.Y', strtotime('noon thursday')); // Per&#351;embe
          }elseif($sonraki_gun=='5'){
          $h_tarihi=date('d.m.Y', strtotime('noon friday')); // Cuma
          }elseif($sonraki_gun=='6'){
          $h_tarihi=date('d.m.Y', strtotime('noon saturday')); // Cumartesi
          }

For this project: http://www.zamanlayici.antenfiyati.com/?lng=en

Adem

Sorry, I wrote wrong, fixing it now

  <select size="8" name="day_of_week[]" id="day_of_week" multiple>  

		<option value="-1" selected="selected">*</option>
		<option value="7">Sunday</option>
		<option value="1">Monday</option>
		<option value="2">Tuesday</option>
		<option value="3">Wednesday</option>
		<option value="4">Thursday</option>
		<option value="5">Friday</option>
		<option value="6">Saturday</option>		
  </select>

Adem

Hello,

True? or False?

$week=array(1,2,3,4,5,6,7);

// if active days of week
if(is_array($_POST['day_of_week']) AND array_intersect($week, $_POST['day_of_week'])){
// if active days of week
}

// if disable days of week
if(is_array($_POST['day_of_week']) AND in_array('-1', $_POST['day_of_week'])){
// if disable days of week
}

jedaisoul

I've never used arrays as $_POST parameters, so I have no idea whether the code is valid, let alone what it will do. More importantly, I do not understand why you need to pass the day-of-week as an array? You are creating an array, $week, anyway.

P.S. Shouldn't $week include 0 (not set) as date("N") can return that value for invalid input?

P.P.S. If you do need to pass info of the "valid" days of the week, I would do so as a string and convert it to an array locally.

Adem

Active week: http://awesomescreenshot.com/0521qgcbaf
Passive week: http://awesomescreenshot.com/09b1qgco5e
Required to submit the form
and
Only me needed if() control

$week=array(1,2,3,4,5,6,7);

// if active days of week
if(is_array($_POST['day_of_week']) AND array_intersect($week, $_POST['day_of_week'])){
// if active days of week
}

// if disable days of week
if(is_array($_POST['day_of_week']) AND in_array('-1', $_POST['day_of_week'])){
// if disable days of week
}

Not the day of the week to determine!

jedaisoul

I do not understand your post, so I cannot offer any assistance.