Need help displaying data from a mysql query

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Need help displaying data from a mysql query

wevie

If I search a database and it returns multiple results, what should I use to grab each result so that I can display each one in the browser. Below is the search and I thought I would use the num_rows variable to how a message if no results are found.

$result = mysql_query("SELECT isbn, bookTitle, bookAuthor, thumbnail FROM BooksForSell WHERE ISBN='".$booksearch."'") or die(mysql_error());
$num_rows  = mysql_num_rows($result);

While the below is not quite formatted the way it will end up looking, I basically want to have a for loop go through the results and show each one in HTML similar to below. I assume that maybe an array would be best for this but I am not sure what the function is to get the results into an array.


echo '
Title: ' .$title. '
Author: ' . $author . ' 
ISBN: ' . $isbn . '
Price: ' .$price' 	
Condition: '. $condition . ' 	
<img src=".$thumbnail.">';

wevie

So here is where I am not. I found most of the following code at php net but I am still not getting anywhere. Am I even close to doing what I need to do? If I am being honest, I am not really familiar with objects in PHP so that is not helping matters in this case.

if(mysqli_connect_errno()){

        echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }
    $query = "SELECT isbn, bookTitle, bookAuthor, thumbnail FROM BooksforSell WHERE isbn='".$bookSearch."'";
    $result = $mysqli->query($query);
    while($newArray = $result->fetch_array()){
        $isbn = $newArray['isbn'];
        $bookTitle = $newArray['bookTitle'];
        $bookAuthor = $newArray['bookAuthor'];
        $thumbnail = $newArray['thumbnail'];

        echo $isbn;
        echo $bookTitle;
        echo $bookAuthor;
        echo $thumbnail;
    }

wevie

And this should have been the first line in the code only with my database info

$mysqli = new mysqli("localhost","user,"password","database");

firesnaker

You have to create a storage array.

$aStorage = new Array();
while($newArray = $result->fetch_array()){
$aStorage[] = array(
            'isbn' => $newArray['isbn'];
            'bookTitle' => $newArray['bookTitle'];
            'bookAuthor' => $newArray['bookAuthor'];
            'thumbnail' => $newArray['thumbnail'];
);
}

Then, somewhere else, you create a loop calling the storage array.

for ($i = 0; $i < count($aStorage); $i++)
{
            echo $aStorage[$i]['isbn'];
            echo $aStorage[$i]['bookTitle'];
            echo $aStorage[$i]['bookAuthor'];
            echo $aStorage[$i]['thumbnail'];
        }

If I may suggest you read up the manual section on Array to get a better understanding of the code.
http://us1.php.net/manual/en/language.types.array.php

In short, an array is a pair of key and value. You call the key to retrieve the value.

Now, to store the data you need a multidimensional array. To be specific, a two-dimensional array.

This should be enough to get you started.

Three-dimensional array and beyond are possible, but rarely used in my experience.

Good luck!

alinarcos

<?php$username="username";
$password="password";$database="your_database";
$field1-name=$POST['Value1'];
$field2-name=$POST['Value2'];
$field3-name=$POST['Value3'];
$field4-name=$POST['Value4'];
$field5-name=$_POST['Value5'];
mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query = "INSERT INTO tablename VALUES('','$field1-name','$field2-name',
'$field3-name','$field4-name','$field5-name')";mysql_query($query);mysql_close();?>

wevie

I tried the code that firesnaker and it did not work. new Array(); seems to be incorrect syntax because that gave me an error. After looking around on php.net, I changed it to just array(), but I was still not getting any data into the array I created.

I have changed my code a bit since the object oriented style is not really making sense to me anyway but I still do not understand how to get the data. I think my problem is that I do not understand how it is returned.

        //creates a query
        $query = "SELECT isbn, bookTitle, bookAuthor, bookCond, thumbnail, price FROM BooksforSell WHERE isbn='".$bookSearch."'";
        //executes a query and returns results
        $result = mysqli_query($dbConnect, $query);
        //assigns the number of rows returned from the query
        $numRows = $result->num_rows;
        $row = mysqli_fetch_array($result, MYSQLI_NUM);

The query I am running in the test returns three rows. I have been looking at php.net and on this if I echo $row[0], $row[1], ......, that will output the first row of data. What I am not understanding is how are the rest of the rows returned? Maybe if I understood that, I could get it.

wevie

Just thought I would update. I have it working, finally but I did run into one really weird thing that I never did figure out. Below is the code to make the array.

$query = "SELECT isbn, bookTitle, bookAuthor, bookCond, thumbnail, price FROM BooksforSell WHERE isbn='".$bookSearch."'";
        //executes a query and returns results
        $result = mysqli_query($dbConnect, $query);
        //assigns the number of rows returned from the query
        $numRows = $result->num_rows;

    $i = 0; //create index and set to 0
    $bookInfo = array(); //create a new empty array
    //iterate through and fill array with data
    while($row = mysqli_fetch_array($result, MYSQLI_NUM)){

            $bookInfo['isbn'][$i] = $row[0];
            $bookInfo['title'][$i] = $row[1];
            $bookInfo['author'][$i] = $row[2];
            $bookInfo['condition'][$i] =$row[3];
            $bookInfo['thumbnail'][$i] = $row[4];
            $bookInfo['price'][$i] = $row[5];

            $i++;

    }//end while loop

The weird thing is when I ran the for loop, the output was always twice the index of the array. I have been testing with a query that returns three results so when the for loop ran, it would run six times with the following code.

for($i=0; $i < count($bookInfo); $i++)

I though maybe is was because I used $i in the while loop but it should be local. Either way, I changed the $i to $j and it still did the same thing. The only way I found to get it to work is by using the row count which I set earlier like so.

for($i=0; $i < $numRows; $i++)

Any ideas as to why this was happening?