Hello Experts,
I am stuck in database query. Well i am making a page which retrieve my database value.
For which below is my code:-
<?php
$con=mysqli_connect("localhost","root","","test");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM testing where flag=1 ");
foreach ($result as $results){
while($row = mysqli_fetch_array($results))
{
echo $row['review'] ;
echo $row['name'] ;
}
}
mysqli_close($con);
?>
When i run the above code it shows me error:
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, array given in /home/stradsol/public_html/test1.php on line 14
I also tried by replacing with:
while($row = mysqli_fetch_array($results, MYSQL_BOTH))
But still the same error 
I am stuck. I dont know what I am missing.
Any help is appreciated.