Thanks shophiarajan47 and Deathshadow,
I think I figured out what you're doing so I did it manually to see if I was right.
<code>
<html>
<head>
<Center>
<script type="text/javascript">
function parseQuery()
{
var myurl = window.location.href;
return (myurl);
}
</script>
<body>
<script>
var myurl=window.onload=parseQuery();
var qs = myurl.split('?')[1];
var rawTxtName = qs.split('&')[0];
var TxtName = rawTxtName.split('=')[1];
var TxtName = TxtName.replace(/+/g, ' ');
var rawOrganization = qs.split('&')[1];
var Organization = rawOrganization.split('=')[1];
var Organization = Organization.replace(/+/g, ' ');
var rawOrganization1 = qs.split('&')[2];
var Organization1 = rawOrganization1.split('=')[1];
var rawSponser = qs.split('&')[3];
var Sponser = rawSponser.split('=')[1];
var Sponser = Sponser.replace(/+/g, ' ');
var rawSponser1 = qs.split('&')[4];
var Sponser1 = rawSponser1.split('=')[1];
var Sponser1 = Sponser1.replace(/+/g, ' ');
var rawResponse = qs.split('&')[5];
var Response = rawResponse.split('=')[1];
var Response = Response.replace(/+/g, ' ');
var rawResponse1 = qs.split('&')[6];
var Response1 = rawResponse1.split('=')[1];
var Response1 = Response1.replace(/+/g, ' ');
var rawCountry = qs.split('&')[7];
var Country = rawCountry.split('=')[1];
var Country = Country.replace(/+/g, ' ');
</script>
<p id="TxtName"></p>
document.getElementById("TxtName").innerHTML = TxtName;
<h1>Terms and Conditions</h1>
<p>Bags are subject to search upon entrance and exit.</p>
<p>Photo ID is Required.</p>
<p>You must be escorted at all times.</p>
<FORM ACTION="http://localhost:80/cgi-bin/sqlconfig.pl" METHOD="POST">
<td><INPUT STYLE="font-size:20px" TYPE="SUBMIT" VALUE="I accept" align="center" ></td>
</body>
</html>
</code>
My question is now, I have to pass this information to my perl script, I'm using
<code>
<p id="TxtName"></p>
document.getElementById("TxtName").innerHTML = TxtName;
</code>
and its not working, what am I doing wrong? (BTW I know my code isn't indented, the indention got lost in the cut and paste)
Thanks
Rick